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[REBOL] Re: Another coffee break problem?

From: tomc:darkwing:uoregon at: 10-Nov-2003 17:34

On Mon, 10 Nov 2003, Gregg Irwin wrote:
> Hi Joel, > > JN> The following 3-by-3 display is a simple magic square: > > JN> 0 8 4 > JN> 5 1 6 > JN> 7 3 2 > > JN> because each row and each column sums to 12. Write a function which > JN> uses the integers 0 thru 8 (once each!) to construct all possible > JN> 3-by-3 simple magic squares. Make it run as quickly as possible. > > No diagonals? I thought magic squares had to work on the diagonal as > well? (not to be nit-picky or anything :) > > -- Gregg
I think that may be why he stipulated "simple" magic squares