[REBOL] Another coffee break problem?
From: joel::neely::fedex::com at: 10-Nov-2003 18:01
If Sunanda will allow me to steal his subject line... ;-)
The following 3-by-3 display is a simple magic square:
0 8 4
5 1 6
7 3 2
because each row and each column sums to 12. Write a function which
uses the integers 0 thru 8 (once each!) to construct all possible
3-by-3 simple magic squares. Make it run as quickly as possible.
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Joel Neely joelDOTneelyATfedexDOTcom 901-263-4446
Enron Accountingg in a Nutshell: 1c=$0.01=($0.10)**2=(10c)**2=100c=$1
