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[REBOL] Re: Another coffee break problem?

From: greggirwin:mindspring at: 10-Nov-2003 18:13

Hi Joel, JN> The following 3-by-3 display is a simple magic square: JN> 0 8 4 JN> 5 1 6 JN> 7 3 2 JN> because each row and each column sums to 12. Write a function which JN> uses the integers 0 thru 8 (once each!) to construct all possible JN> 3-by-3 simple magic squares. Make it run as quickly as possible. No diagonals? I thought magic squares had to work on the diagonal as well? (not to be nit-picky or anything :) -- Gregg