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[REBOL] Re: Removing a key-value pair from a hash?

From: carl:cybercraft at: 23-Feb-2002 23:08

On 23-Feb-02, Alex Liebowitz wrote:
> How would one write a function to take a hash and a key, and remove > the key and the value that key is associated with from the hash? > With O(1) time, preferably. > Here's an example (let's call our function search-remove): > the-hash: make hash! ["si" "yes" "hola" "hello"] > search-remove the-hash "hola" > After this expression was complete, the-hash would have the value: > make hash! ["si" "yes"] > Alex
I've not done anything with hash before, but treating it like a normal block seems to work, though whether it has any unexpected effects on the hash's index or speed I'm not sure. Others would know. Anyway, this gives the results you asked for... search-remove: func [a-hash [hash!] a-str [string!]][ head remove remove find a-hash a-str ]
>> the-hash: make hash! ["si" "yes" "hola" "hello"]
== make hash! ["si" "yes" "hola" "hello"]
>> search-remove the-hash "hola"
== make hash! ["si" "yes"]
>> the-hash
== make hash! ["si" "yes"] and...
>> the-hash: make hash! ["si" "yes" "hola" "hello" "kia ora" "g'day"]
== make hash! ["si" "yes" "hola" "hello" "kia ora" "g'day"]
>> search-remove the-hash "hola"
== make hash! ["si" "yes" "kia ora" "g'day"]
>> the-hash
== make hash! ["si" "yes" "kia ora" "g'day"] HTH. -- Carl Read