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[REBOL] Re: Using a Math oper. buried in a variable

From: henrikmk:g:mail at: 2-Apr-2009 22:42

On Thu, Apr 2, 2009 at 10:37 PM, <mumpsoid-gmx.com> wrote:
> On Thu, 2 Apr 2009, Wall, Scott wrote: > >> >> Hi Duke, >> >> > As with most things in REBOL, there are a number of ways to do what >> > you want. Here's another one: >> >> >>> num1: 6 >> >== 6 >> >>> num2: 5 >> >== 5 >> >>> op: :* >> >>> op num1 num2 >> >== 30 >> >>> print [op num1 num2] >> >30 >> >> Still another way is to leave >> op: "*" >> and use: >> do reform [num1 op num2] >> >> Scott >> > JOY!!!!!!!! > >>> >>> num1 > == 5 >>> num2 > == 6 >>> op > == * >>> do reform [num1 op num2] > == 30 >>> > > Is it OK for me to think that this is a PITA?
Actually, it's only one form: Code is data and data is code, but the method above creates a string, which is fast in REBOL2 due to the string being in ASCII format, but slower in R3, because it's converted to unicode and away from unicode. I believe the most correct and fastest method here is to assign the function directly to 'op, so you don't have to put things inside a block. It was mentioned earlier:
>> op: :* >> op num1 num2
== 30 -- Regards, Henrik Mikael Kristensen