World: r3wp

That is great but also of no help if a word is holding the path
   'foo/bar
I was hoping the solution was in
   to-lit-word

path: 'foo/bar
join path 'ton ; ??

fails with 
  ** Script Error: Cannot use path on word! value

Hmm, works here.

to-path reduce[path 'word]   ; works OK but what a klunk

Only if the blocks are literaly embedded.
Could you try with the example
  t1
  t2

join to-path 't2 't1

no, in the example that I posted above :-)

>> t1: [a "one" b "two" c "three"]

>> t2: [f t1]

'f has no value so it is just like a functor
I am not askeing to be able to just use
   t2/f/a
with no further ado
I must build the path
   newPath: to-path reduce [ t2/f  'a]

is a pain ( and only because of how to-path is implemented;  to-lit-path 
is no more help as far as I can see at this hour

I'm not sure why -- newPath: join 't2/f 'a -- doesn't work...

Hold on, -- join to-path t2/f 'a --??

That just caused Rebol 2.6.3 to blow away
I did not send teh missuve to Microsoft that I was proffered

the missive

It works on 2.6.2 (Mac) 2.7.5 (Win)

let me fire up Rebo/View again

but how will this help me where I have a WORD that is holding that 
initial, partial, path ?

join to-path do path 'a

path: 't2/f
do join to-path do path 'a

;same error
>> t1: [a "one"]
== [a "one"]
>> t2: [f t1]
== [f t1]
>> pp: join 't2/f 'a
== t2/f/a
>> do pp
** Script Error: Cannot use path on word! value
** Where: halt-view
** Near: t2/f/a
>>

2.6.3 just ditched me again with that one ...

This is the limitation of evaluating paths.  'do does not evalute 
't1 when it is returned from 't2/f

I think 2.6.3 does not want 'path used as a word ;-)

so do you think that   
   to-path reduce [ my-path  'my-next-refinement]
the best that I can do?

If your interpreter chokes on 'join, then I guess so...

I could try just Rebol/Core and see if that make a difference

It is not very often that Rebol blows out on me ... I can't remember 
when last before I started looking at my functor issues

That's 3 times tonight with only 2 teeny blocks and 2 paths  and 
no do against any file and nothing added to user.r

ah-ha !
Works fine in Rebol/Core  ! 

path: 't2/f
do join to-path do path 'a

Nope.

Back to View and this time Rebol did not blow out of the water .... 

Is there a dump.log that I can look at see what these fatal errors 
have been ?

Not sure.  Try working with -- trace on

>> t1: [a "one"]
== [a "one"]
>> t2: [f t1]
== [f t1]
>> path: 't2/f
== t2/f
>> do join to-path do path 'a
== "one"
; thanks CHRIS

Hey, if it works : )

I would not have stumbled on the 
   do path
any too soon, I fear ... ;-)

It's not the most intuitive move, for sure.

I am adding 
   augpath: func [{augment path with a word}
to my armory

Now to find out what typo of mine is able to blow 2.6.3 outa the 
wadder

augpath: func [{ augment a PATH with a WORD }path 'word] [
      return join to-path reduce[path] :word]
; augpath t2/f a

oops!
IGnoring the needless return,  that is one word longer than

>> pword: func [path 'word /local blk] [
    to-path reduce[path :word]]
; ;-)

; I mean
 augpath: func [path 'word ] [
    to-path reduce[path :word]]

; but IN the interpreter, to use join
>> do join to-path do my-path 'a-further-refinement
; is terrific and has led me to
my-path:  to-path join reduce[ my-path ] 'a-deeper-tag

Nope 
another typo
  my-path: t2/f
That is trivial
It has to be 
  my-path: 't2/f
or
  my-path: to-path [t2 f]

JOIN does a reduce, so that's probably your problem. to-path reduce 
is not doing what you expect there, it's creating a path inside a 
path (no wonder it may crash :).

use append copy path word

also, you need to reduce your blocks above, because you have words 
in them, not subblocks.

Thanks.  I should also have used a type block in my func 

   augpath: func [ {augment a path with a word} path [path!] functor 
   [ word! ] /local p ] [

Once there are only subblocks it becomes trivial;  I have been trying 
to augment a path! series which starts with a block in which a tagged-word 
is bound to a block .  By augment the path I mean to return a path, 
not the result of evaluating the path
  t1: [ a-word-with-no-value-functor "one" ]

  t2: [ functor t1 ]  ; t1 is a word, not a block, but is bound to 
  a block at the time the path is extended into it ( if possible without 
  t2 being an object! )
  t2: context [ functor t1] ; also trivial

; this work fine for traversal
>> navpath: func [ pth [path!] 'wrd [word!] /local p42 ] [
[    p42: do pth
[    to-path reduce [p42 :wrd]]
>> pp: navpath path a
== t1/a
>> do pp
== "one"

where path was
path: to-path [ t2 f ]

>> t1
== [a "one"]
>> t2: context [f: t1]
>> t2/f
== [a "one"]
>> t2/f/a
== "one"
>> first t1
== a
>> get first t1
** Script Error: a has no value
** Where: halt-view
** Near: get first t1
>> get first third t2
== [a "one"]

>> do append copy 't2/f 'a
== "one"