World: r3wp
[Core] Discuss core issues
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Graham 11-Oct-2008 [11069] | >> isset?: :value? >> isset? 'test == false >> isset? 'rebol == true |
Henrik 11-Oct-2008 [11070] | don't you have to be careful with the binding when doing value? to-word "something" ? |
Terry 11-Oct-2008 [11071] | Im using it to check a parsed block to see if the value is set.. is there a better way? |
Claude 11-Oct-2008 [11072x2] | hi, i would like to know how to open a port with rebol in FTP to connect a ISERIES or IBM I or AS400 and execute commande like this on "quote namemft 1" or "cd /" or "quote syscmd call a PGM" |
i would like to do it like in dos windows that the FTP command can take a file as input and then execute all commands in that file | |
BrianH 11-Oct-2008 [11074x4] | If you do to-word "something" in R2 the word returned will be bound to the global context, so it will only have a value if a word of that name in the global context already has a value. It doesn't matter if you do to-word in a function. |
Terry, I have found that the best way to check if a value has been set to a word in a parse rule, the best way is to set the word to none before you run the parse rule (or at the beginning of the rule in a paren), then check to see if it is still none afterwards. | |
You can use NONE? to do that, or the checker for whatever datatype you are looking for if you want a positive result. The IF function also treats NONE as false, so if you are not looking for logic values you can use it directly. Like this: a: none parse [1 2 3] [set a integer!] ; will return false if a [ ; you found it, do something ] If you think the value you are testing might be an active value (like a function), refer to it with a get-word! for safety, like :a. | |
The none technique especially words for string parsing and the copy operation because it sets the word to none if there was an empty string copied, useful to know. | |
Graham 11-Oct-2008 [11078] | Claude you'll have to write your own ftp client |
Terry 11-Oct-2008 [11079x2] | Brian, that works fine, but now I need to set 200+ words to /local in my function? |
When doing a 'parse block', what's the best way to localize a couple hundred words for post parsing? | |
Chris 12-Oct-2008 [11081x2] | ; pre-process the parse block? -- localize: func [block /local word words rule][ words: copy [] rule: [set word any-word! (append words word) | into [any rule]] parse block [any rule] forall words [words/1: to-word words/1] use words compose/only [(block)] ] parse series localize rule |
Could be tidied up a little with an exceptions option... | |
Terry 12-Oct-2008 [11083] | can't seem to get it to fire.. do you have a working example by chance? |
Chris 12-Oct-2008 [11084x5] | >> parse "str" localize [a: "str" (probe b: a)] "str" == true >> a ** Script Error: a has no value ** Near: a >> b == "str" |
I guess 'into doesn't go into paren! in 2.7.6? | |
; perhaps I forgot something: localize: func [block /local word words rule][ words: copy [] rule: [set word any-word! (append words word) | into [any rule] | skip] parse block [any rule] forall words [words/1: to-word words/1] use words compose/only [(block)] ] | |
Anyhow, could use some work, just throwing out the idea... | |
localize: func [block /with except /local word words rule][ words: copy [] rule: [set word any-word! (append words word) | into [any rule] | skip] parse block [any rule] forall words [words/1: to-word words/1] words: difference unique union words except except use words compose/only [(block)] ] parse "string" localize/with [a: "str" (probe a) copy b "ing" (probe b)][probe] | |
Gabriele 13-Oct-2008 [11089] | Anton, yes, as Brian says, that looks like a bug. |
Anton 13-Oct-2008 [11090] | Well, I guess a bug report is due then. Who's responsibility is it ? Graham - I think you :) |
BrianH 13-Oct-2008 [11091] | Terry, you should consider structuring your parse rules so that you can do more processing of the data you recognize on the fly in parens. When you are using a hundred local words and doing your processing afterwards, you are repeating yourself. |
Gregg 13-Oct-2008 [11092] | Will, I got away from lit-word! params because they're a pain when you're doing more dynamic things in code. As soon as you want to compute the arg, they get in the way. My classic example is an INCR function. For control funcs, I think they make the calling code read more naturally, and the cases where they cause problems there are much less frequent. |
Davide 15-Oct-2008 [11093] | hi, I need your help with bind: - I have an object h h: make object! [ q: [] ] append h/q make object! [ f1: func [a][print ["f1" a]] f2: func [b][f1 join "f2 " b] ] if I call f1 and f2 the results are correct: >> h/q/1/f1 "hi" f1 hi >> h/q/1/f2 "hi" f1 f2 hi --------------------- Now, I want to make the code of f2 dynamic, so I add a second param "code" to f2: h/q/1/f2: func [b code][do code] of course this doesn't work, f1 and b aren't bound: >> h/q/1/f2 "hi" [f1 join "f2 " b] ** Script Error: f1 has no value ** Where: f2 ** Near: f1 join "f2 " b I've tried with no luck the followings: h/q/1/f2: func [b code][do bind code 'f2] h/q/1/f2: func [b code][do bind code in h/q/1 'f2] What is the magic word: "do bind code ******* " ? |
Anton 15-Oct-2008 [11094x3] | The 'f2 word which you are trying to use as an example word is not bound to the object you want, because you create the function after making the object. If you had defined the function which does the bind directly in the object spec to start with you wouldn't have this problem. But if you need to define the function after creating the object, then you could do any of these: |
h/q/1/f2: func [b code][do bind bind code 'b h/q/1] h/q/1/f2: func [b code][do bind bind code 'b in h/q/1 'self] h/q/1/f2: func [b code] compose [do bind bind code 'b (h/q/1)] h/q/1/f2: func [b code] compose [do bind bind code 'b (to-lit-word in h/q/1 'self)] h/q/1/f2: func [b code] compose [do bind bind code 'b (to-lit-word in h/q/1 'f1)] | |
The first alternative looks the simplest to me. :) The extra BIND to one of F2's locals ('b) is necessary if CODE ever refers to any of F2's locals (B or CODE). (This avoids the next error message you were going to get. :) | |
Davide 15-Oct-2008 [11097] | double bind ! Thanks Anton, it works |
Geomol 15-Oct-2008 [11098] | Learn to bind knots with REBOL lecture one. ;) I always have trouble with BIND. Maybe I didn't ever take the time to really get it. So much to investigate with this language. :) |
amacleod 16-Oct-2008 [11099x2] | How do I convert: [{some sentence with some carriage returns and tabs}] to: [{some sentence with^/^-some carriage returns^/^-^-and tabs}] |
Is there a simple method or do I need to parse through and append each line while inserting the ^/ | |
Sunanda 16-Oct-2008 [11101] | This may have side effects, removing extra spaces: x: [{some sentence with { some carriage returns { and tabs}] >> trim first x == "some sentence with^/some carriage returns^/and tabs" |
Anton 16-Oct-2008 [11102] | Geomol, I was like that too, for quite some time, at the beginning. But... we can teach it to you !! It's really a simple concept. |
Geomol 16-Oct-2008 [11103x2] | I know the concept of a context. I actually use the word CONTEXT in most of my scripts. And reading the BIND help (with ? bind), I see, it binds words to a known word. So I guess, the known word is defining the context, the new words (1. argument of BIND) should bind to. But why, Anton, do you use two binds in your example? I would guess, something like: do bind [code b] h/q/1 should work? |
amacleod, you might get confused by some small inconsistent in REBOL? >> {a { ^-b} == "a^/^-b" >> {a { ^-b { ^-c} == {a ^-b ^-c} | |
Sunanda 16-Oct-2008 [11105] | Amacleod -- please ignore my effort -- it fails to retain the tabs. Sorry! |
Geomol 16-Oct-2008 [11106] | (My last example was from the console, in case it isn't obvious.) |
Anton 16-Oct-2008 [11107x4] | Geomol, yes the known word just defines the context. I use two binds because there are two contexts involved - the h/q/1 context, and the function's context. (Each time you create a function, a context is created for its locals.) |
do bind [code b] ctx would not do what we want, because it would only bind the two words in the block ('code and 'b) to the context. | |
What we want is to bind the words *inside* the block that 'code refers to. Bind considers each word inside the block, checking to see if they are in the target context. If so, they are rebound to the target context. This step essentially gives the words a useful meaning, the meaning that's intended, and the meaning that's defined in the target context, not in some other context like the global context. | |
So BIND selectively "paints" a context over words in a block. BIND recurses into sub-blocks to do this, but does not get the value of words and recurse into them too, if they are blocks. This is why bind [code] ctx does not affect the CODE block; it only affects the 'code word (and only that instance of the 'code word, not any other instances floating around elsewhere in the system, in their own blocks.) | |
Geomol 16-Oct-2008 [11111] | What we want is to bind the words *inside* the block that 'code refers to. Ah yes. I get it now. |
Davide 16-Oct-2008 [11112] | Would be easier (for me) to have something like "do/bind-here code", where all words in the code are bound in the context where there is the "do". |
Anton 16-Oct-2008 [11113] | Davide, that is not possible in rebol, because there is no concept of "here". That is, there is no "current" context. That's just an illusion created by groups of words travelling together in blocks. Every word has its own binding. Just because several words in a block often have the same binding does not mean that the block knows anything of the context. This word-binding is a unique feature of rebol, and people used to other languages confuse it for scope, which is less flexible. |
Geomol 16-Oct-2008 [11114] | Why is it, that b is not auto-bound to the function in this example? >> f: func [b code] [do code] >> f "hi" [print b] ** Script Error: b has no value I mean, passing [print b] as an argument to the function, it's just a block of words without meaning initially. When handed to f, f takes over and will now do it. So f has to find out, what's the meaning of the inside of the block. First it finds the word "print", which makes sense. Then it find the word "b", and this doesn't makes sense to f. Why not? |
amacleod 16-Oct-2008 [11115x3] | Why: >> {a { b { c} == "a^/b^/c" but: {a { ^-b { ^-^-c} == {a ^-b ^-^-c} |
I need the entire text sting on one line... | |
{a^/^-b^/^-^-c} | |
Geomol 16-Oct-2008 [11118] | Yes, it's one of the 'funny' corners of REBOL. Are you sure, you really need it on one line? What are you doing with the string? |
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