[REBOL] Re: Using a Math oper. buried in a variable
From: mumpsoid:gmx at: 2-Apr-2009 14:52
On Thu, 2 Apr 2009, Henrik Mikael Kristensen wrote:
> On Thu, Apr 2, 2009 at 10:37 PM, <mumpsoid-gmx.com> wrote:
> >
> > On Thu, 2 Apr 2009, Wall, Scott wrote:
> >
> >>
> >> Hi Duke,
> >>
> >> > As with most things in REBOL, there are a number of ways to do what
> >> > you want. Here's another one:
> >>
> >> >>> num1: 6
> >> >== 6
> >> >>> num2: 5
> >> >== 5
> >> >>> op: :*
> >> >>> op num1 num2
> >> >== 30
> >> >>> print [op num1 num2]
> >> >30
> >>
> >> Still another way is to leave
> >> op: "*"
> >> and use:
> >> do reform [num1 op num2]
> >>
> >> Scott
> >>
> > JOY!!!!!!!!
> >
> >>>
> >>> num1
> > == 5
> >>> num2
> > == 6
> >>> op
> > == *
> >>> do reform [num1 op num2]
> > == 30
> >>>
> >
> > Is it OK for me to think that this is a PITA?
>
> Actually, it's only one form: Code is data and data is code, but the
> method above creates a string, which is fast in REBOL2 due to the
> string being in ASCII format, but slower in R3, because it's converted
> to unicode and away from unicode.
>
> I believe the most correct and fastest method here is to assign the
> function directly to 'op, so you don't have to put things inside a
> block. It was mentioned earlier:
>
> >> op: :*
> >> op num1 num2
> == 30
>
>> about
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>> op: :*
>> op num1 num2
== 30
>>
Cool!
but I would have never fingered that out in a million years. :)
--
Duke Normandin
A: Because it messes up the order in which people normally read text.
Q: Why is top-posting such a bad thing?
A: Top-posting.
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