[REBOL] Re: Counting chars (was Simple things should be simpl e to do ?)
From: rsnell::webtrends::com at: 16-Nov-2000 16:15
It's really the hash that makes it easy. I have an
associative array (that I call a map - much easier to type)
that I use all the time. Given my map, my count routine
becomes:
s: "sdfsdfsdfsdfsdfsd"
m: make map! []
foreach c s [
m/set c ((to-integer m/get c) + 1)
]
repeat i m/length? [
print [(first at m/keys i) (first at m/vals i)]
]
s 6
d 6
f 5
Almost as easy as Perl if you don't take into account the code for the map
(which I have not included).
If you don't have a map (associative array) in your toolbox, get one.
It can make some functions a lot easier. If anyone wants I can post
the source to mine but others have been posted by better Rebolers
at various times.
Rodney
