[REBOL] Re: Bug! in assignment to date! values with stacked set-path values
From: rotenca:telvia:it at: 14-Nov-2002 18:12
Hi Ladislav
> It means, that [(a)] should contain a paren! containing a word as it did,
> but (a)/(b) shall differ from (a) / (b), i.e. parens shall be treated
> specifically - neither as possible word characters, nor as ordinary
> delimiters.
...
> This case doesn't matter, any solution is acceptable to me.
Only this? Well: everything was clear from the beginning. :-)
> OTOH, it is OK to obtain:
>
> length? [(a) / (b)] ; == 3
>
> What do you think?
I agree. I should like at least to use compose on path:
b: 1
compose a/(b) ;== a/1
and get-word in this case:
>> x: func [/a][a]
>> b: 'a;== a
>> x/:b ;==true
Now the latter print none as it would called without any refinement and this
seems to me a bug.
> One may try to check an analogical situation: [a]/[b] versus [a] / [b]. What
> would be the best solution in that case?
Is a too radical proposal the following?
[[a] 2]/[a] ; ==2
[a 2 b 3]/b ; ==3
a: [[a] 1 [b] 2]
a/[b];==2
a/([b]) ;==2
Going in this direction we'll can embed a whole Rebol program in a path!
instead of a block! :-)
---
Ciao
Romano
