Parse question

Which wasn't much better, right? :-) I gather this is what you were attempting... st: "Kai was here" parse/all st [thru "ai" copy chunk to "here"] Change the parse to... parse/all st [thru "ai" copy chunk to "here" to end] and it should work. Also, I don't think /all has any effect when parsing a block. Can others confirm that? -- Carl Read.

str: { Hi Parsers ~ =A0 why does parse below not return= true? =A0 Thanks, Kai =A0 =A0 >>=A0st: "Kai was= here" == "Kai was here" >>=A0parse/all st [ thruai copy chunk to "here" ] == false >>=A0probe= chunk " was " == " was " >> --} letternum: charset[#"A" - #"Z" #"0" - #"9"] parse/all str[ any[to "=" [p: "=" 2 letternum (remove/part p 3) :p ] | skip] ] replace/all str " >>" "^/!>>" replace/all str "= " " " ? str { STR is a string of value: { Hi Parsers ~ why does parse below not return true? Thanks, Kai !>>st: "Kai was here" "Kai was here" !>>parse/all st [ thruai copy chunk to "here" ] false !>>probe chunk " was " " was " !>> --} Ok, now i get it. :) because the string must match upto the end. In your example the parsing goes to the "here", not thru, so not skipping it. you must skip that yourself. Some variants: to "here" to end ;; not exact, stuff can follow after "here" to "here" "here" ;; goes to "here" and then skips to "here" 4 skip ;; "" its somewhat ugly, having something like this would be nice: to "here" skip-last }

-- -Volker Any problem in computer science can be solved with another layer of indirection. But that usually will create another problem. David Wheeler