[REBOL] Re: variable number of arguments
From: lmecir:mbox:vol:cz at: 27-Nov-2000 9:57
Hi Larry,
you *are* correct, of course, but your list is not complete.
> Hi Andrew, Ladislav
>
> This example may help resolve the question in a direct fashion. We can use
> do/next to identify the first expression in a block.
>
> >> x: 1 y: 2 z: 3
> == 3
>
> >> do/next [do x y z]
> == [1 [y z]]
>
> This shows that the inner do consumed only one argument.
>
> >> take2: func [x y] ["hello"]
> >> do/next [take2 x y z]
> == ["hello" [z]]
>
> This shows the function take2 consumed (as expected) two arguments.
>
> Cheers
> -Larry
>
take-n: func [n /local spec] [
spec: copy []
for i 1 n 1 [
append spec to word! append copy "a" to string! i
]
func spec reduce [:reduce append reduce [to lit-word! append copy "take"
to string! n] spec]
]
do/next [do take-n 4 1 2 3 4 5]
== [[take4 1 2 3 4] [5]]
shows, that Do took 5 arguments here, IMO.
Regards
Ladislav
