[REBOL] Re: More on expressions
From: rotenca:telvia:it at: 2-Feb-2003 11:35
Look down to see my solution: any [all [(a > b) xor (a > c) a] all [(a > c) xor (b > c) c] b] --- Ciao Romano
[REBOL] Re: More on expressionsFrom: rotenca:telvia:it at: 2-Feb-2003 11:35
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