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[REBOL] Re: IDIOMS: setting multiple words

From: joel:neely:fedex at: 10-Oct-2003 7:37

Hi, Elan and all, Elan wrote:
> Hi Sunanda: > >> >> set [foo bar baz] copy [] > > You will find that only foo is set set to a block, whereas bar and baz > are initialized to the value none. This is unlike using > set [foo bar baz[] 3 ;- (i.e. some non-series value > where all words will be initialized to the same value. >
Actually, all of FOO BAR and BAZ will be set to NONE, as the empty list is the source of *all* values for the three words:
>> set [foo bar baz] copy []
== []
>> foo
== none
>> bar
== none
>> baz
== none
>>
-jn-