[REBOL] Re: dynamic pairs

From: semseddinm:bircom at: 11-Nov-2009 13:36

Yes it is faster than the other methods:

>> a: 2 b: 3 d: now/precise loop 500000 [t: (1x0 * a) + (0x1 * b)]
difference now/precise d
== 0:00:00.187

>> a: 2 b: 3 d: now/precise loop 500000 [t: as-pair a b] difference
now/precise d
== 0:00:00.281

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