[REBOL] Re: Sort by first part of line
From: greggirwin:mindspring at: 6-Sep-2002 11:36
Hi Scott,
Good deal! I used your data generator and then did this:
data: read/lines %data-1.txt
compare-items: func [a b /local aa bb] [
aa: to integer! first parse a none
bb: to integer! first parse b none
either aa = bb [0][either aa < bb [-1][1]]
]
t: now/time/precise
sort/compare data :compare-items
print now/time/precise - t
halt
which gave me these results for 3 runs (on a P900 w/384 Meg of RAM):
1. 0:00:20.099
2. 0:00:20.269
3. 0:00:20.099
Changing the comparisons to use Sunanda's approach (assuming equality is
least likely): either aa < bb [-1][either aa > bb [1][0]]
1. 0:00:19.508
2. 0:00:19.528
3. 0:00:19.518
Making the data a hash! didn't speed it up and trying to make it a list!
didn't work. Even just a plain SORT on the list didn't work, and inserted
'end for some items. Haven't investigated.
The data looks stable at a glance. Not verified though.
>> data
== [" 000 c3wef22aeka 33" " 000 aw333afk c2e 2e" " 000 ake3c2we3 3a2f" "
000 wa2k2c ee3 3fa3" " 000 wa fc32a2k3ee 3" " 000 3k3e32...
--Gregg
