[REBOL] got my brainfart parse answer
From: timewarp:sirius at: 6-Jun-2001 14:26
remember bo?
this is what he showed me:
>> rule: [thru "x" mark: to "y" y: :mark to "z" z: (either (index? y) <
index? z [a: copy/part mark y][a: copy/part mark z])]
>> parse "x .... ab z cd y" rule
== false
>> a
== " .... ab "
>> parse "x .... ab cd y z" rule
== false
>> a
== " .... ab cd "
and, this is what i wanted. unfortunately, it's not
what i wanted to see... now i have to redesign my
data structures as well as a significant portion of
the script... *sigh*
cheerfulness,
-----EAT
--
Erin A. Thomas --- == --- (707) 463-8578
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