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[REBOL] Re: Simple parse question

From: lmecir:mbox:vol:cz at: 14-Apr-2003 23:49

Hi Tom, myself and all, ...
> but that get into a loop same as it would without the 'break. > > more confusing is the result > > >> result copy [] parse {Don't "Mess Up"} words > >> result > == ["Don't" {"Mess} {Up"} "Don't" {"Mess} {Up"} none none none ... ... > > the string is duplicated, and there is a long run of 'none. > > (this is /core 2.5.5 on solaris) > I wonder whether this deserves a feedback or not, but it > doesn't look
allright to me, that is why I asked. Romano explained, that the BREAK keyword influences just the behaviour of a block rule containing BREAK, in this case not the block with ANY, but the block with the alternative. That is why it works this way. Regards -Ladislav