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[REBOL] Re: Hungarian Alphabet Sort (was Re: Collation sequence - proper and eff

From: gscottjones:mchsi at: 17-May-2002 13:52

From: "Carl Read"
> The new version's faster, but not > markedly so. Perhaps 30% faster going by the single test of a long > list of random words I did, though it's still 7 or 8 times slower than > REBOL's sort. Maybe if it was all done with parsing it'd be faster, > but I'd have to re-think it all. (: > > Anyway, here it is. See the end of the mail for how to handle > characters that are to be considered equal. ie "A" & "a" etc. <snip> > Now, to give the same weight to two or more characters, enclose them > in a block. They can either be a single string in the block, in > which case all the characters in the string are weighted the same, > else they can be group of strings which will all be weighted the > same. ie... <snip> > Also, I've allowed for characters not included in the rules, they > being treated as the last character in the rule. So this doesn't > generate an error... <snip> > As before, no promises about how well this will perform with real > alphabets, but it should be a bit better than the last effort. > Hopefully. (;
By George, I think you've done it! At least it appears to sort the sample Hungarian word list correctly. That is a slick solution. It is about 35% faster than my original effort. Good job. I like the way you handled the characters of equivalent weight, although I've not put this apsect through any testing. Good job! --Scott Jones