[REBOL] Re: What does "loop" return?
From: valeri:mytinski:gma:il at: 5-Apr-2009 14:23
05.04.2009, =D7 10:34, Graham Chiu =CE=C1=D0=C9=D3=C1=CC(=C1):
> If you wish to create a new empty block each time, you would do this =20
> instea
> d
>
> loop 2 [ append copy [] 3 ]
>
> which would be the same as
>
> append [ ] 3 append [ ] 3
>
> Graham Chiu
Thanks for this example.
Sorry, now I understood nothing.
Why
loop 2 [append [] 3]
is equivalent to
append append [] 3 3
that is some sort of "nested" expressions - result of first 'append is
INSERTED as parameter for second 'append,
while
loop 2 [ append copy [] 3 ]
is equivalent to
append [ ] 3 append [ ] 3
that is some sort of "sequence" expressions - first 'append is
FOLLOWED by second 'append? Why does not parameter substitution
done?
Valeri
