Expected behaviour or a bug?

[1/5] from: carl:cybercraft at: 3-Dec-2002 7:00

>> [a/b/c d/e/f g/h/i]

== [a/b/c d/e/f g/h/i]

>> [a/b/c /d/e/f g/h/i]

== [a/b/c /d /e /f g/h/i] Should that happen with the middle path? -- Carl Read

[2/5] from: g::santilli::tiscalinet::it at: 2-Dec-2002 19:48

Hi Carl, On Monday, December 2, 2002, 7:00:27 PM, you wrote:

>>> [a/b/c /d/e/f g/h/i]

CR> == [a/b/c /d /e /f g/h/i] CR> Should that happen with the middle path? Yes, because it is not a path for REBOL. It takes it as three distinct refinements. (The only way to know if REBOL should have behaved differently here, would be to ask to Carl S...) Regards, Gabriele. -- Gabriele Santilli <[g--santilli--tiscalinet--it]> -- REBOL Programmer Amigan -- AGI L'Aquila -- REB: http://web.tiscali.it/rebol/index.r

[3/5] from: rotenca:telvia:it at: 2-Dec-2002 19:50

hi Carl.

> >> [a/b/c /d/e/f g/h/i] > == [a/b/c /d /e /f g/h/i] > > Should that happen with the middle path?

Rebol sees 3 refinements. A path can't start with /. In this case / is taken as a divisor. --- Ciao Romano

[4/5] from: anton:lexicon at: 3-Dec-2002 14:41

I think Romano meant to say delimiter. Anton.

[5/5] from: rotenca:telvia:it at: 3-Dec-2002 15:16

Hi Anton,

> I think Romano meant to say delimiter.

Thanks, my english is very bad! --- Ciao Romano