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A few questions about words

 [1/7] from: eric:mccinc at: 19-Oct-2000 13:28


I seem to be misunderstanding the use of words in rebol. say I had the following code word1: "This is a word" word2: 'word1 is there any way using word2 to access and set the value of word1? It seems to me that I should be able to. I guess what I am asking is if a function is passed a variable name can us then use that to modify and access the value. If I am completly off the mark on this one let me know. Thanks Eric Merritt

 [2/7] from: larry:ecotope at: 19-Oct-2000 10:47


Hi Eric
>> word1: "This is a word"
== "This is a word"
>> word2: 'word1
== word1
>> get word2
== "This is a word"
>> word3: 'word2
== word2
>> get get word3
== "This is a word" This process can be carried out to any depth. HTH -Larry

 [3/7] from: ryanc:iesco-dms at: 19-Oct-2000 10:54


This might help...
>> word1: "test"
== "test"
>> type? word1
== string!
>> word2: 'word1 ;this assigns word2 to the word word1 not its value
== word1
>> type? word2
== word!
>> word2
== word1
>> word3: word1 ;word1 is naturally evaluated to "test" then assigned
== "test"
>> type? word3
== string!
>> word3
== "test"
>> word4: :word1 ;this method takes the value of word1 without evaluation.
== "test"
>> type? word4
== string!
>> word1: "TTTTT"
== "TTTTT"
>> word4
== "test"
>> word3
== "test"
>>
Something else you should know...
>> p1: print
** Script Error: print is missing its value argument. ** Where: p1: print
>> p1: :print ;skips evaluation of print, just gets its value. >> p1 "me"
me
>>
--Ryan [eric--mccinc--com] wrote:
> I seem to be misunderstanding the use of words in rebol. > say I had the following code
<<quoted lines omitted: 10>>
> [rebol-request--rebol--com] with "unsubscribe" in the > subject, without the quotes.
-- Ryan Cole Programmer Analyst www.iesco-dms.com 707-468-5400 I am enough of an artist to draw freely upon my imagination. Imagination is more important than knowledge. Knowledge is limited. Imagination encircles the world. -Einstein

 [4/7] from: christian::ensel::gmx::de at: 19-Oct-2000 20:06


Hi Eric, look at the following console session:
>> word1: "initial value"
== "initial value"
>> set 'word1 "new value"
== "new value"
>> word1
== "new value"
>> word2: 'word1
== word1
>> set word2 "even newer value"
== "even newer value"
>> word1
== "even newer value" The above makes use of the fact that SET expects a LIT-WORD! to determine which word it should assign the value to.
> If I am completly off the mark on this one let me know.
You're not ;-) Look at
>> f1: func ['word] [print ["Function was called on word" word]] >> ; ^^^^^ >> f1 some-word
Function was called on word some-word
>> f1 'some-word
Function was called on word some-word
>> f2: func [word] [print ["Function was called on" word]] >> ; ^^^^ >> f2 some-word
** Script Error: some-word has no value. ** Where: f2 some-word
>> f2 'some-word
Function was called on word some-word Regards Christian [Christian--Ensel--GMX--De]

 [5/7] from: rebol:svendx:dk at: 19-Oct-2000 20:30


Hello [eric--mccinc--com], You can use get and set: ## word1: "This is a word" == "This is a word" ## word2: 'word1 == word1 ## word2 == word1 ## get word2 == "This is a word" ## set word2 "It still is" == "It still is" ## word1 == "It still is" (## is my rebol prompt...) /Thomas On 19-Oct-00, [eric--mccinc--com] wrote:

 [6/7] from: eric:mccinc at: 19-Oct-2000 14:41


Hey larry, This my be a stupid question but does it work the same way for set?as in word1: "Hello World" word2: 'word1 set word2 "New World" print world1
>>New world
Thanks

 [7/7] from: arolls:bigpond:au at: 27-Oct-2000 20:44


Hi Eric,
>> set :word2 "no it isn't, it's a string"
== "no it isn't, it's a string"
>> get word2
== "no it isn't, it's a string" Anton.

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