to-word questions...

[ bob: func [] [ print "Hi, I'm Bob" ] [ ]

== function!

Hi, I'm Bob == unset!

** Script Error: Invalid path value: ?function?. ** Where: type? test/:bob How do I find out if test/bob is a function?

Hi, I'm Ray

== word!

== false

== function! Is the type lost for good? It looks like what I need a get-word function

Here you are evaluating text/bob. the function bob in the object is is evaluated which leads to the evaluation of the expression print "Hi, I'm Bob". The print function does not return a value, which in REBOL evaluates to the value unset. The unset value is passed to type? which returns the type of unset. The type of unset is unset!

You must have defined a global function called bob in addition to the bob function defined in the test object. If you didn't have a global bob function defined, then the error you would be getting here would be:L ** Script Error: bob has no value. ** Where: test/:bob However, if I define a global bob function, then I get the same error as you do. Your error reports that REBOL has first evaluated the expression :bob. It evluated to a function, and now REBOL is trying to use the function as part of the path test/:bob. I.e. the path REBOL is dealing with is test/?function? (?function? is the internal tag used to designate a function). REBOL is complaining that you cannot use a value of type function! as part of a path construct.

try

== function!

Not exactly surprising. You converted the string "ray" into a word using to word!. Of course the its type is a word!. What else?

Of course the expression to word! "ray" does not return a function. It returns the word ray. And since word! <> function!, function? will report that the value ray of type word! is not a value of type fnction!

Here REBOL first retrieves ray's value, which is the function it is associated wtih, and passes the function value to type? I.e. the type? function never gets to see the word ray. The rype? function reports the type of the value associated with ray. And that is a value of type function!

The type is not lost for good.

Here it is:

== function! Hope this helps, Elan