[REBOL] Re: parse again
From: al:bri:xtra at: 28-Dec-2000 13:48
> I have a diary I want to parse like this:
>
> test: { 9.00 am Get up 9.30 am have breakfast 10.00 am read email }
An alternative is to use block! parse:
>> test: [ 9:00 "Get up" 9:30 "Have breakfast" 10:00 "read email"]
== [9:00 "Get up" 9:30 "Have breakfast" 10:00 "read email"]
>> parse test [any [time! string!]]
== true
Of course, that requires that the data be in Rebol compatible format.
> I want to copy all the entries for each time period, including the time,
to a list.
> I tried:
>
> digit: charset "0123456789"
>
> parse test [ to 1 2 digit (print 1) ]
'to is a little limited. It only seems to work with string! or end.
What you need is something like:
Test: { 9.00 am Get up 9.30 am have breakfast 10.00 am read email}
Diary: make block! 0
Digit: charset "0123456789"
LoAlpha: charset "abcdefghijklmnopqrstuvwxyz"
HiAlpha: charset "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
Alpha: union LoAlpha HiAlpha
Time: [1 2 Digit "." 2 Digit ["am" | "pm"]]
parse test [
any [
copy TimeEntry Time copy Entry some [Alpha | " "] (
repend Diary [TimeEntry trim Entry]
)
| skip
]
end
]
>> Diary
== ["9.00 am" "Get up" "9.30 am" "have breakfast" "10.00 am" "read email"]
I hope that helps!
Andrew Martin
ICQ: 26227169 http://members.nbci.com/AndrewMartin/
