[REBOL] Re: Parse versus Regular Expressions
From: g:santilli:tiscalinet:it at: 3-Apr-2003 11:10
Hi Ladislav,
On Thursday, April 3, 2003, 9:39:43 AM, you wrote:
LM> Noticeably, the "dumb" approach to the equation rewriting:
LM> y: [[y #"a"] | #"b"]
LM> didn't "fire" any error, stack overflow, or any unusual exception. Nevertheless,
it didn't work:
LM> parse "b" y ; == true
LM> parse "ba" y ; == false
LM> Any ideas?
>> r: [r]
== [r]
>> parse "abc" r
== false
It looks like, that PARSE notices the endless loop, and makes the
rule fail.
Regards,
Gabriele.
--
Gabriele Santilli <[g--santilli--tiscalinet--it]> -- REBOL Programmer
Amigan -- AGI L'Aquila -- REB: http://web.tiscali.it/rebol/index.r
