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[REBOL] Re: [Mutability bitset] Puzzle (*very hard*!)

From: greggirwin:mindspring at: 29-Sep-2006 9:40

Hi Ladislav,
>> LM> *Is there a way how to discern equal bitsets that don't reference >> LM> "identical" underlying bitset?* >> >> My first instinct would be to toggle a bit in one bitset, compare >> them, then toggle it back. >>
LM> yes, it was easy, as it looks. The only hard part may be, if the LM> bitsets are a bit "nonstandard", like e.g. #[bitset! #{00}] You should always be able to use an integer! value with FIND/INSERT/REMOVE, to toggle the low bit. You may also want to compare the bitset lengths, if that's important. -- Gregg