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[REBOL] Embedded Object and Scope - again...

From: coussement:c:itc:mil:be at: 9-May-2001 10:53

Hi list: ---------------------------------------------------- Sorry for insisting, but it's the first time one of my question stays unanswered, and I need the answer badly ;-P I still hope somebody will help me (perhaps at RT) so I repost my question... ---------------------------------------------------- I tried the following:
<snip>
ancestor-object: make object! [ global-obj-prop: make integer! 0 init: func [ val [integer!] ][ global-obj-prop: make integer! val ] embedded-object: make object! [ print-global-obj-prop: does [print global-obj-prop] ] ] </snip> Ok, so I tried:
>> ancestor-object/init 10
== 10
>> ancestor-object/embedded-object/print-global-obj-prop
10 No problem here :-)
>> descendant-object: make ancestor-object [] >> descendant-object/init 20
== 20
>> descendant-object/embedded-object/print-global-obj-prop
10 Ouch, not what I thought... Let's check... In the "Official Guide", pg 348, I found: <quote> The ancestor object and the descendant object share the same embedded object. </quote> OK, so I tried something else:
>> descendant-object: make ancestor-object [descendant-embedded-object: make
embedded-object []]
>> descendant-object/init 20
== 20
>> descendant-object/descendant-embedded-object/print-global-obj-prop
10 Again, not what I thought ... I was awaiting 20 !!! ;-( Here are my questions: 1. Why did RT choose for such implementation ? What are the advantages ? 2. Why did my last try not work - it was -IMHO- logical I should get a result of 20 ..., as I instanciated the embedded object within the instanciation of the ancestor object. 2. How can I get my descendant-embedded-object to retrieve the property of it's container, the descendant-object ? Thx for answering :-)) chr==